JEE Math Practice Question
If for a positive integer n, the quadratic equation $$x\left( {x + 1} \right) + \left( {x + 1} \right)\left( {x + 2} \right)$$$$ + .... + \left( {x + \overline {n - 1} } \right)\left( {x + n} \right)$$$$ = 10n$$ has two consecutive integral solutions, then n is equal to :
- A.9
- B.10
- C.11
- D.12
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