JEE Math Practice Question
If x is a solution of the equation, $$\sqrt {2x + 1} $$ $$ - \sqrt {2x - 1} = 1,$$ $$\,\,\left( {x \ge {1 \over 2}} \right),$$ then $$\sqrt {4{x^2} - 1} $$ is equal to :
- A.$${3 \over 4}$$
- B.$${1 \over 2}$$
- C.2
- D.$$2\sqrt 2 $$
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