JEE Math Practice Question
Let two numbers have arithmetic mean 9 and geometric mean 4. Then these numbers are the roots of the quadratic equation
- A.$${x^2} - 18x - 16 = 0$$
- B.$${x^2} - 18x + 16 = 0$$
- C.$${x^2} + 18x - 16 = 0$$
- D.$${x^2} + 18x + 16 = 0$$
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