JEE Math Practice Question
The value of '$$a$$' for which one root of the quadratic equation $$$\left( {{a^2} - 5a + 3} \right){x^2} + \left( {3a - 1} \right)x + 2 = 0$$$ is twice as large as the other is
- A.$$ - {1 \over 3}$$
- B.$$ {2 \over 3}$$
- C.$$ - {2 \over 3}$$
- D.$$ {1 \over 3}$$
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