JEE Math Practice Question
If $$\alpha \ne \beta $$ but $${\alpha ^2} = 5\alpha - 3$$ and $${\beta ^2} = 5\beta - 3$$ then the equation having $$\alpha /\beta $$ and $$\beta /\alpha \,\,$$ as its roots is
- A.$$3{x^2} - 19x + 3 = 0$$
- B.$$3{x^2} + 19x - 3 = 0$$
- C.$$3{x^2} - 19x - 3 = 0$$
- D.$${x^2} - 5x + 3 = 0$$
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