JEE Math Practice Question
If $$2 \sin ^3 x+\sin 2 x \cos x+4 \sin x-4=0$$ has exactly 3 solutions in the interval $$\left[0, \frac{\mathrm{n} \pi}{2}\right], \mathrm{n} \in \mathrm{N}$$, then the roots of the equation $$x^2+\mathrm{n} x+(\mathrm{n}-3)=0$$ belong to :
- A.$$(0, \infty)$$
- B.Z
- C.$$\left(-\frac{\sqrt{17}}{2}, \frac{\sqrt{17}}{2}\right)$$
- D.$$(-\infty, 0)$$
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