JEE Math Practice Question
Let $$S=\left\{\theta \in\left(0, \frac{\pi}{2}\right): \sum\limits_{m=1}^{9} \sec \left(\theta+(m-1) \frac{\pi}{6}\right) \sec \left(\theta+\frac{m \pi}{6}\right)=-\frac{8}{\sqrt{3}}\right\}$$. Then
- A.$$ S=\left\{\frac{\pi}{12}\right\} $$
- B.$$ S=\left\{\frac{2 \pi}{3}\right\} $$
- C.$$ \sum\limits_{\theta \in S} \theta=\frac{\pi}{2} $$
- D.$$ \sum\limits_{\theta \in S} \theta=\frac{3\pi}{4} $$
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