JEE Math Practice Question
If n is the number of solutions of the equation $$2\cos x\left( {4\sin \left( {{\pi \over 4} + x} \right)\sin \left( {{\pi \over 4} - x} \right) - 1} \right) = 1,x \in [0,\pi ]$$ and S is the sum of all these solutions, then the ordered pair (n, S) is :
- A.(3, 13$$\pi$$ / 9)
- B.(2, 2$$\pi$$ / 3)
- C.(2, 8$$\pi$$ / 9)
- D.(3, 5$$\pi$$ / 3)
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