JEE Math Practice Question
Considering the principal values of the inverse trigonometric functions, $\sin ^{-1} (\frac{\sqrt{3}}{2} x+\frac{1}{2} \sqrt{1-x^2} ),-\frac{1}{2}
- A.$\frac{-5 \pi}{6}-\sin ^{-1} x$
- B.$\frac{5 \pi}{6}-\sin ^{-1} x$
- C.$\frac{\pi}{6}+\sin ^{-1} x$
- D.$\frac{\pi}{4}+\sin ^{-1} x$
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