JEE Math Practice Question
The value of $ \cot^{-1} \left( \frac{\sqrt{1 + \tan^2(2)} - 1}{\tan(2)} \right) - \cot^{-1} \left( \frac{\sqrt{1 + \tan^2\left(\frac{1}{2}\right)} + 1}{\tan\left(\frac{1}{2}\right)} \right) $ is equal to
- A.$ \pi - \frac{3}{2} $
- B.$ \pi + \frac{5}{2} $
- C.$ \pi - \frac{5}{4} $
- D.$ \pi + \frac{3}{2} $
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