JEE Math Practice Question
If $\frac{\pi}{2} \leq x \leq \frac{3 \pi}{4}$, then $\cos ^{-1}\left(\frac{12}{13} \cos x+\frac{5}{13} \sin x\right)$ is equal to
- A.$x+\tan ^{-1} \frac{5}{12}$
- B.$x-\tan ^{-1} \frac{4}{3}$
- C.$x+\tan ^{-1} \frac{4}{5}$
- D.$x-\tan ^{-1} \frac{5}{12}$
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