JEE Math Practice Question
Let $$x=\frac{m}{n}$$ ($$m, n$$ are co-prime natural numbers) be a solution of the equation $$\cos \left(2 \sin ^{-1} x\right)=\frac{1}{9}$$ and let $$\alpha, \beta(\alpha >\beta)$$ be the roots of the equation $$m x^2-n x-m+ n=0$$. Then the point $$(\alpha, \beta)$$ lies on the line
- A.$$3 x-2 y=-2$$
- B.$$3 x+2 y=2$$
- C.$$5 x+8 y=9$$
- D.$$5 x-8 y=-9$$
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