JEE Math Practice Question

Let (a, b) $\subset(0,2 \pi)$ be the largest interval for which $\sin ^{-1}(\sin \theta)-\cos ^{-1}(\sin \theta)>0, \theta \in(0,2 \pi)$, holds. If $\alpha x^{2}+\beta x+\sin ^{-1}\left(x^{2}-6 x+10\right)+\cos ^{-1}\left(x^{2}-6 x+10\right)=0$ and $\alpha-\beta=b-a$, then $\alpha$ is equal to :

1. A.$\frac{\pi}{16}$
2. B.$\frac{\pi}{48}$
3. C.$\frac{\pi}{8}$
4. D.$\frac{\pi}{12}$