JEE Math Practice Question
$$\tan \left(2 \tan ^{-1} \frac{1}{5}+\sec ^{-1} \frac{\sqrt{5}}{2}+2 \tan ^{-1} \frac{1}{8}\right)$$ is equal to :
- A.1
- B.2
- C.$$\frac{1}{4}$$
- D.$$\frac{5}{4}$$
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