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JEE Math Practice Question

If $${({\sin ^{ - 1}}x)^2} - {({\cos ^{ - 1}}x)^2} = a$$; 0 < x < 1, a $$\ne$$ 0, then the value of 2x2 $$-$$ 1 is :

  1. A.$$\cos \left( {{{4a} \over \pi }} \right)$$
  2. B.$$\sin \left( {{{2a} \over \pi }} \right)$$
  3. C.$$\cos \left( {{{2a} \over \pi }} \right)$$
  4. D.$$\sin \left( {{{4a} \over \pi }} \right)$$

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