JEE Math Practice Question
If $$\sum\limits_{r = 1}^{50} {{{\tan }^{ - 1}}{1 \over {2{r^2}}} = p} $$, then the value of tan p is :
- A.$${{101} \over {102}}$$
- B.$${{50} \over {51}}$$
- C.100
- D.$${{51} \over {50}}$$
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