JEE Math Practice Question
2$$\pi $$ - $$\left( {{{\sin }^{ - 1}}{4 \over 5} + {{\sin }^{ - 1}}{5 \over {13}} + {{\sin }^{ - 1}}{{16} \over {65}}} \right)$$ is equal to :
- A.$${{7\pi } \over 4}$$
- B.$${{5\pi } \over 4}$$
- C.$${{3\pi } \over 2}$$
- D.$${\pi \over 2}$$
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