JEE Math Practice Question
The domain of the function f(x) = $${\sin ^{ - 1}}\left( {{{\left| x \right| + 5} \over {{x^2} + 1}}} \right)$$ is (– $$\infty $$, -a]$$ \cup $$[a, $$\infty $$). Then a is equal to :
- A.$${{\sqrt {17} - 1} \over 2}$$
- B.$${{1 + \sqrt {17} } \over 2}$$
- C.$${{\sqrt {17} } \over 2} + 1$$
- D.$${{\sqrt {17} } \over 2}$$
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