JEE Math Practice Question
Let $${\tan ^{ - 1}}y = {\tan ^{ - 1}}x + {\tan ^{ - 1}}\left( {{{2x} \over {1 - {x^2}}}} \right),$$ where $$\left| x \right| < {1 \over {\sqrt 3 }}.$$ Then a value of $$y$$ is :
- A.$${{3x - {x^3}} \over {1 + 3{x^2}}}$$
- B.$${{3x + {x^3}} \over {1 + 3{x^2}}}$$
- C.$${{3x - {x^3}} \over {1 - 3{x^2}}}$$
- D.$${{3x + {x^3}} \over {1 - 3{x^2}}}$$
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