JEE Math Practice Question
The trigonometric equation $${\sin ^{ - 1}}x = 2{\sin ^{ - 1}}a$$ has a solution for :
- A.$$\left| a \right| \ge {1 \over {\sqrt 2 }}$$
- B.$${1 \over 2} < \left| a \right| < {1 \over {\sqrt 2 }}$$
- C.all real values of $$a$$
- D.$$\left| a \right| \le {1 \over {\sqrt 2 }}$$
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