JEE Math Practice Question
$\lim \limits_{x \rightarrow \infty} \frac{\left(2 x^2-3 x+5\right)(3 x-1)^{\frac{x}{2}}}{\left(3 x^2+5 x+4\right) \sqrt{(3 x+2)^x}}$ is equal to :
- A.$\frac{2 e}{3}$
- B.$\frac{2}{3 \sqrt{\mathrm{e}}}$
- C.$\frac{2 \mathrm{e}}{\sqrt{3}}$
- D.$\frac{2}{\sqrt{3 \mathrm{e}}}$
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