JEE Math Practice Question
$$\mathop {\lim }\limits_{t \to 0} {\left( {{1^{{1 \over {{{\sin }^2}t}}}} + {2^{{1 \over {{{\sin }^2}t}}}}\, + \,...\, + \,{n^{{1 \over {{{\sin }^2}t}}}}} \right)^{{{\sin }^2}t}}$$ is equal to
- A.$${{n(n + 1)} \over 2}$$
- B.n
- C.n$$^2$$ + n
- D.n$$^2$$
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