JEE Math Practice Question
Let $$f(x) = \left\{ {\begin{matrix} {{x^3} - {x^2} + 10x - 7,} & {x \le 1} \\ { - 2x + {{\log }_2}({b^2} - 4),} & {x > 1} \\ \end{matrix} } \right.$$. Then the set of all values of b, for which f(x) has maximum value at x = 1, is :
- A.($$-$$6, $$-$$2)
- B.(2, 6)
- C.$$[ - 6, - 2) \cup (2,6]$$
- D.$$\left[ {-\sqrt 6 , - 2} \right) \cup \left( {2,\sqrt 6 } \right]$$
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