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JEE Math Practice Question

If $$\mathop {\lim }\limits_{n \to \infty } \left( {\sqrt {{n^2} - n - 1} + n\alpha + \beta } \right) = 0$$, then $$8(\alpha+\beta)$$ is equal to :

  1. A.4
  2. B.$$-$$8
  3. C.$$-$$4
  4. D.8

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