JEE Math Practice Question
$$\mathop {\lim }\limits_{x \to {1 \over {\sqrt 2 }}} {{\sin ({{\cos }^{ - 1}}x) - x} \over {1 - \tan ({{\cos }^{ - 1}}x)}}$$ is equal to :
- A.$$\sqrt 2 $$
- B.$$ - \sqrt 2 $$
- C.$${1 \over {\sqrt 2 }}$$
- D.$$ - {1 \over {\sqrt 2 }}$$
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