JEE Math Practice Question

The value of $$\mathop {\lim }\limits_{x \to 1} {{({x^2} - 1){{\sin }^2}(\pi x)} \over {{x^4} - 2{x^3} + 2x - 1}}$$ is equal to:

1. A.$${{{\pi ^2}} \over 6}$$
2. B.$${{{\pi ^2}} \over 3}$$
3. C.$${{{\pi ^2}} \over 2}$$
4. D.$$\pi$$2