JEE Math Practice Question
If $$\mathop {\lim }\limits_{x \to 0} {{{{\sin }^{ - 1}}x - {{\tan }^{ - 1}}x} \over {3{x^3}}}$$ is equal to L, then the value of (6L + 1) is
- A.$${1 \over 6}$$
- B.$${1 \over 2}$$
- C.6
- D.2
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