JEE Math Practice Question
The value of the limit $$\mathop {\lim }\limits_{\theta \to 0} {{\tan (\pi {{\cos }^2}\theta )} \over {\sin (2\pi {{\sin }^2}\theta )}}$$ is equal to :
- A.0
- B.$$-$$$${1 \over 2}$$
- C.$${1 \over 4}$$
- D.$$-$$$${1 \over 4}$$
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