JEE Math Practice Question
The value of $$\mathop {\lim }\limits_{x \to {0^ + }} {{{{\cos }^{ - 1}}(x - {{[x]}^2}).{{\sin }^{ - 1}}(x - {{[x]}^2})} \over {x - {x^3}}}$$, where [ x ] denotes the greatest integer $$ \le $$ x is :
- A.$$\pi$$
- B.$${\pi \over 4}$$
- C.$${\pi \over 2}$$
- D.0
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