JEE Math Practice Question
Let f : S $$ \to $$ S where S = (0, $$\infty $$) be a twice differentiable function such that f(x + 1) = xf(x). If g : S $$ \to $$ R be defined as g(x) = loge f(x), then the value of |g''(5) $$-$$ g''(1)| is equal to :
- A.1
- B.$${{187} \over {144}}$$
- C.$${{197} \over {144}}$$
- D.$${{205} \over {144}}$$
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