JEE Math Practice Question
Let $${S_k} = \sum\limits_{r = 1}^k {{{\tan }^{ - 1}}\left( {{{{6^r}} \over {{2^{2r + 1}} + {3^{2r + 1}}}}} \right)} $$. Then $$\mathop {\lim }\limits_{k \to \infty } {S_k}$$ is equal to :
- A.$${\cot ^{ - 1}}\left( {{3 \over 2}} \right)$$
- B.$${\pi \over 2}$$
- C.tan$$-$$1 (3)
- D.$${\tan ^{ - 1}}\left( {{3 \over 2}} \right)$$
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