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JEE Math Practice Question

If $$\alpha $$ is positive root of the equation, p(x) = x2 - x - 2 = 0, then $$\mathop {\lim }\limits_{x \to {\alpha ^ + }} {{\sqrt {1 - \cos \left( {p\left( x \right)} \right)} } \over {x + \alpha - 4}}$$ is equal to :

  1. A.$${1 \over \sqrt2}$$
  2. B.$${1 \over 2}$$
  3. C.$${3 \over \sqrt2}$$
  4. D.$${3 \over 2}$$

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