JEE Math Practice Question
$$\mathop {\lim }\limits_{x \to {1^ - }} {{\sqrt \pi - \sqrt {2{{\sin }^{ - 1}}x} } \over {\sqrt {1 - x} }}$$ is equal to :
- A.$$\sqrt {{2 \over \pi }} $$
- B.$${1 \over {\sqrt {2\pi } }}$$
- C.$$\sqrt {{\pi \over 2}} $$
- D.$$\sqrt \pi $$
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