JEE Math Practice Question

Let f(x) = 5 – |x – 2| and g(x) = |x + 1|, x $$ \in $$ R. If f(x) attains maximum value at $$\alpha $$ and g(x) attains minimum value at $$\beta $$, then $$\mathop {\lim }\limits_{x \to -\alpha \beta } {{\left( {x - 1} \right)\left( {{x^2} - 5x + 6} \right)} \over {{x^2} - 6x + 8}}$$ is equal to :

1. A.$${1 \over 2}$$
2. B.$$-{1 \over 2}$$
3. C.$${3 \over 2}$$
4. D.$$-{3 \over 2}$$