JEE Math Practice Question
$$\mathop {\lim }\limits_{x \to 0} {{x\tan 2x - 2x\tan x} \over {{{\left( {1 - \cos 2x} \right)}^2}}}$$ equals :
- A.$${1 \over 4}$$
- B.1
- C.$${1 \over 2}$$
- D.$$-$$ $${1 \over 2}$$
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