JEE Math Practice Question
$$\mathop {\lim }\limits_{x \to 0} \,\,{{{{\left( {27 + x} \right)}^{{1 \over 3}}} - 3} \over {9 - {{\left( {27 + x} \right)}^{{2 \over 3}}}}}$$ equals.
- A.$${1 \over 3}$$
- B.$$-$$ $${1 \over 3}$$
- C.$$-$$ $${1 \over 6}$$
- D.$${1 \over 6}$$
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