JEE Math Practice Question
Let $$p = \mathop {\lim }\limits_{x \to {0^ + }} {\left( {1 + {{\tan }^2}\sqrt x } \right)^{{1 \over {2x}}}}$$ then $$log$$ $$p$$ is equal to :
- A.$${1 \over 2}$$
- B.$${1 \over 4}$$
- C.$$2$$
- D.$$1$$
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