JEE Math Practice Question
$$\mathop {\lim }\limits_{x \to 0} \,{{{{\left( {1 - \cos 2x} \right)}^2}} \over {2x\,\tan x\, - x\tan 2x}}$$ is :
- A.$$-$$ 2
- B.$$-$$ $${1 \over 2}$$
- C.$${1 \over 2}$$
- D.2
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