JEE Math Practice Question
$$\mathop {\lim }\limits_{x \to 0} {{\left( {1 - \cos 2x} \right)\left( {3 + \cos x} \right)} \over {x\tan 4x}}$$ is equal to
- A.$$ - {1 \over 4}$$
- B.$${1 \over 2}$$
- C.1
- D.2
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