JEE Math Practice Question
If $S$ and $S^{\prime}$ are the foci of the ellipse $\frac{x^2}{18}+\frac{y^2}{9}=1$ and P be a point on the ellipse, then $\min \left(S P \cdot S^{\prime} P\right)+\max \left(S P \cdot S^{\prime} P\right)$ is equal to :
- A.$3(6+\sqrt{2})$
- B.$3(1+\sqrt{2})$
- C.27
- D.9
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