JEE Math Practice Question
The length of the chord of the ellipse $\frac{x^2}{4}+\frac{y^2}{2}=1$, whose mid-point is $\left(1, \frac{1}{2}\right)$, is :
- A.$\frac{2}{3} \sqrt{15}$
- B.$\frac{1}{3} \sqrt{15}$
- C.$\sqrt{15}$
- D.$\frac{5}{3} \sqrt{15}$
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