JEE Math Practice Question
The length of the chord of the ellipse $\frac{x^2}{25}+\frac{y^2}{16}=1$, whose mid point is $\left(1, \frac{2}{5}\right)$, is equal to :
- A.$\frac{\sqrt{1691}}{5}$
- B.$\frac{\sqrt{2009}}{5}$
- C.$\frac{\sqrt{1541}}{5}$
- D.$\frac{\sqrt{1741}}{5}$
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