JEE Math Practice Question
If the points of intersections of the ellipse $${{{x^2}} \over {16}} + {{{y^2}} \over {{b^2}}} = 1$$ and the circle x2 + y2 = 4b, b > 4 lie on the curve y2 = 3x2, then b is equal to :
- A.12
- B.10
- C.6
- D.5
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