JEE Math Practice Question

Let the line y = mx and the ellipse 2x2 + y2 = 1 intersect at a ponit P in the first quadrant. If the normal to this ellipse at P meets the co-ordinate axes at $$\left( { - {1 \over {3\sqrt 2 }},0} \right)$$ and (0, $$\beta $$), then $$\beta $$ is equal to :

1. A.$${{\sqrt 2 } \over 3}$$
2. B.$${2 \over 3}$$
3. C.$${{2\sqrt 2 } \over 3}$$
4. D.$${2 \over {\sqrt 3 }}$$