JEE Math Practice Question
If the line x – 2y = 12 is tangent to the ellipse $${{{x^2}} \over {{a^2}}} + {{{y^2}} \over {{b^2}}} = 1$$ at the point $$\left( {3, - {9 \over 2}} \right)$$ , then the length of the latus rectum of the ellipse is :
- A.5
- B.9
- C.$$8\sqrt 3 $$
- D.$$12\sqrt 2 $$
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