JEE Math Practice Question
The eccentricity of an ellipse whose centre is at the origin is $${1 \over 2}$$. If one of its directrices is x = – 4, then the equation of the normal to it at $$\left( {1,{3 \over 2}} \right)$$ is :
- A.2y – x = 2
- B.4x – 2y = 1
- C.4x + 2y = 7
- D.x + 2y = 4
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