JEE Math Practice Question
The locus of the foot of perpendicular drawn from the centre of the ellipse $${x^2} + 3{y^2} = 6$$ on any tangent to it is :
- A.$$\left( {{x^2} + {y^2}} \right) ^2 = 6{x^2} + 2{y^2}$$
- B.$$\left( {{x^2} + {y^2}} \right) ^2 = 6{x^2} - 2{y^2}$$
- C.$$\left( {{x^2} - {y^2}} \right) ^2 = 6{x^2} + 2{y^2}$$
- D.$$\left( {{x^2} - {y^2}} \right) ^2 = 6{x^2} - 2{y^2}$$
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