JEE Math Practice Question
The ellipse $${x^2} + 4{y^2} = 4$$ is inscribed in a rectangle aligned with the coordinate axex, which in turn is inscribed in another ellipse that passes through the point $$(4,0)$$. Then the equation of the ellipse is :
- A.$${x^2} + 12{y^2} = 16$$
- B.$$4{x^2} + 48{y^2} = 48$$
- C.$$4{x^2} + 64{y^2} = 48$$
- D.$${x^2} + 16{y^2} = 16$$
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