JEE Math Practice Question
If the circles $$(x+1)^2+(y+2)^2=r^2$$ and $$x^2+y^2-4 x-4 y+4=0$$ intersect at exactly two distinct points, then
- A.$$\frac{1}{2}<\mathrm{r}<7$$
- B.$$3<\mathrm{r}<7$$
- C.$$5<\mathrm{r}<9$$
- D.$$0<\mathrm{r}<7$$
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