JEE Math Practice Question
If one of the diameters of the circle $$x^2+y^2-10 x+4 y+13=0$$ is a chord of another circle $$\mathrm{C}$$, whose center is the point of intersection of the lines $$2 x+3 y=12$$ and $$3 x-2 y=5$$, then the radius of the circle $$\mathrm{C}$$ is :
- A.4
- B.3$$\sqrt2$$
- C.6
- D.$$\sqrt{20}$$
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